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The three parallel resistors are equivalent to a single 2 ω resistor, because. This 2 ω resistance is in series with the given 2 ω resistor, so their equivalent resistance is 2 + 2 = 4 ω. Therefore, three times as much current will flow through this equivalent 4 ω resistance in the top branch as through the parallel 12 ω. Therefore, to calculate the power dissipated by the resistor, the formulas are as follows: